Answer to September 20, 1999 Problem |
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adapted from a problem by Bob Stanton in the September 1999 issue of Games
During the night, Abe woke up, stole half of Bob's
coins and half of Cal's, added them to his own
bag, and went back to sleep. At this point,Abe
had 300 coins. How many did each thief bring? |
Answer to the Problem:
Abe brought 75 coins. Bob brought 150 coins. Cal brought 300 coins.
Let x = number of coins that Abe brought.
Therefore, Abe must have brought 75 coins, so x =75.
Since the number of coins that Bob brought equals the
number of coins that he wound up with,
y = y/4 + z/8 + 75
Solving these two equations simultaneously, |
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