Seven guests at a restaurant came,
The first every day,
The second every other day,
The third every third day,
and so on to
the seventh who came once a week.
When will they all come to dine at the
restaurant on the same day? (What is the smallest number of days?)
Solution to Problem: Answer is 420 days.
The least common multiple of 1, 2, 3, 4, 5, 6, and 7 is 420.
Correctly solved by:
1. Devin Grim | Winchester, VA |
2. Trey Genda | Winchester, VA |
3. John Beavers | Winchester, VA |
4. Rachel Rasmussen | Winchester, VA |
5. Jason Aikens | Winchester, VA |
6. Barrett Waybright | Winchester, VA |