Seven guests at a restaurant came,
The first every day,
The second every other day,
The third every third day,
and so on to
the seventh who came once a week.
When will they all come to dine at the
restaurant on the same day?
(What is the smallest number of days?)
Solution to the Problem:
Answer is 420 days.
The least common multiple of 1, 2, 3, 4,
5, 6, and 7 is 420.