The angles of a triangle are in the ratio 3:4:5.
If the shortest side has a length of 1 meter,
what is the length of the longest side?
Solution to Problem:
The answer is (1 + \/3) / 2 meters or approximately 1.36 meters
First, determine the measures of the angles
using 3x + 4x + 5x = 180 degrees.
The angles measure 45, 60, and 75 degrees
respectively.
(1) You can solve the problem by basic geometry if you draw an altitude from the vertex of the 75 degree angle to the opposite base (the longest side). This altitude divides the original triangle into two smaller triangles (a 45-45-90 triangle and a 30-60-90 triangle). You can now determine the measures of all the sides.
(2) An alternative method is to use the Law of Sines
to set up the problem.
Call the length of the short side S and the length
of the longest side L.
Then sin(75) / L = sin(45) / S
Since S = 1 meter, sin (75) = .9659258 and sin(45) =
.7071,
it follows that L = 1.366 meters.
Correctly solved by:
| 1. Jon Pence | Winchester, VA |
| 2. Jia Ran | Rome, Italy |
| 3. Bob Hearn | Winchester, VA |