The key to this problem is that the 5 parts that are congruent in the 2 triangles are not the corresponding parts. Otherwise, the triangles would be congruent by SSS or SAS...
All three pairs of angles must be congruent.
The three pairs of sides can not be congruent or
else it would be SSS.
Here is an example of how this can work:
Triangle ABC is similar to triangle DEF.
Thus, five pairs of parts are congruent, but the sixth pair is not congruent.Triangle ABC Triangle DEF ------------ ------------ angle A = angle D angle B = angle E angle C = angle F side AB = 18 side EF = 18 side AC = 12 side DE = 12 side BC = 27 side DF = 8
AB BC AC 18 27 12 -- = -- = -- or -- = -- = -- DE EF DF 12 18 8 3 which all reduce to --- 2
1. Jon Pence | Winchester, VA |