April 3, 2000
Problem of the Month

The Six Integer Problem

From the integers 1, 2, 3, 4, 5, 6, 7, 8, and 9, can you find six different integers, call them A, B, C, D, E, and F such that A x B x C = D x E x F ?

Solution to the Problem:

A = 1
B = 8
C = 9
D = 3
E = 4
F = 6

Thus, 1 x 8 x 9 = 72 = 3 x 4 x 6

or

A = 2
B = 3
C = 6
D = 1
E = 4
F = 9

Thus, 2 x 3 x 6 = 36 = 1 x 4 x 9

Correctly solved by:

1. Jia Ran	Rome, Italy
2. Josh Grewal	Winchester, VA
3. Richard Mocarski	Winchester, VA
4. Sam Stiebel	Winchester, VA
5. Tom Marino	Winchester, VA
6. Christopher March *	Winchester, VA
7. Chris Moats	Winchester, VA
8. Elizabeth Cotter	Oak Hill, VA
9. Chip Schewikarth	Winchester, VA
10. James O'Kane	Winchester, VA
11. David Pugh	Winchester, VA
12. Kirstine Wynn	Winchester, VA
13. Joe Jenkins	Winchester, VA
14. Court Pifer	Winchester, VA

* Found both solutions using a computer program he wrote in C++

Send any comments or questions to: David Pleacher