In honor of PI DAY (3/14), you will need to use pi in your solution of this
week's problem.
There are three circles, each tangent to the other two.
The radius of circle A is 6 inches.
The radius of circle B is 4 inches.
The radius of circle C is 2 inches.
The following facts were used to solve this problem:
Observe that the shaded area (in red in the diagram above) is equal to the area of triangle ABC minus the areas of the three sectors (these are shown as tan, grey, and cyan in the diagram below).
The area of triangle ABC = 1/2 * 6 * 8 = 24 square inches.
The measure of angle C has been determined to be 90°,
so sector C is 1/4 of the area of
circle C (since 90 / 360 = 1/4).
The area of sector C = 1/4 * pi * 22
= pi = 3.1419 square inches.
To determine angle B: B = Tan-1
(8/6) = 53.130°.
The area of sector B = 53.130/360 * pi * 4
2
= 7.41836 square inches.
1. Keith Mealy | Cincinnati, Ohio |
2. Jim Arrison | Norristown, Pennsylvania |
3. Arsalan Heydarian | Harrisonburg, Virginia |
4. William Proffitt | Winchester, Virginia |
5. James Alarie | University of Michigan -- Flint, Flint, Michigan |
6. Jeffrey Gaither | Winchester, Virginia |
7. Nathan Seifert | Harrisonburg, Virginia |
8. Wajih Ansari | Harrisonburg, Virginia |
9. Jaime Garcia | Virginia Tech, Blacksburg, Virginia |
10. James Simmons | Harrisonburg, Virginia |
11. Walt Arrison | Philadelphia, Pennsylvania |
12. Rich Murray | Ridgetown, Ontario, Canada |
13. Michael Singer | Winchester, Virginia |
14. António Baptista | Lisboa, Portugal |
15. Tom Robb | Winchester, Virginia |
16. Carrie Wilson | Ticonderoga, New York |
17. Daniel Surber | Winchester, Virginia |
18. Trey Mason | Winchester, Virginia |
19. Tristan Collins | Winchester, Virginia |
20. Misty Carlisle | Winchester, Virginia |
21. Kailen Ko | Winchester, Virginia |