Hockey Standings are based on points:
Each win is 2 points,
Each loss is 0 points,
Each tie is 1 point.
In this league, each team plays each other once.
Fill in the missing numbers in the standings:
Team | Games played | Wins | Losses | Ties | Goals Made | Goals Allowed | Points |
---|---|---|---|---|---|---|---|
A | 4 | 7 | 1 | 5 | |||
E | 2 | 2 | 6 | 0 | |||
D | 4 | 5 | 3 | ||||
C | 3 | 0 | 4 | 3 | |||
B | 5 | 2 |
Solution to the problem:
Team | Games played | Wins | Losses | Ties | Goals Made | Goals Allowed | Points |
---|---|---|---|---|---|---|---|
A | 4 | 2 | 1 | 1 | 7 | 1 | 5 |
E | 2 | 0 | 2 | 0 | 2 | 6 | 0 |
D | 4 | 1 | 2 | 1 | 5 | 10 | 3 |
C | 3 | 0 | 0 | 3 | 4 | 4 | 3 |
B | 3 | 2 | 0 | 1 | 5 | 2 | 5 |
First, recognize that if one game is played, it shows up as two games in the standings because two teams were involved. Also,
a total of two points will show up in the standings (either a tie in which both teams get one point; or a win and a loss, in which
one team gets 2 points and the other none).
Since E has no points, it must have lost both of its games.
So, you can fill in 0 - 2 - 0 for its record.
Since C has 3 points, and 3 games and no losses, it must have 3 ties and no wins. So, you can fill in its record.
Also, since all of its games were tied, they must have scored 4 goals. Since the total goals scored must
equal the total goals allowed, team D must have allowed 10 goals.
For team B, games played must have been 1 or 3, since the total of games played must be even, and the most games that a
team could play would be 4 (if they have played each of the other teams once). If they had played 1 game,
their ppoints would be 3 (the total of the games would be 14 which means the total points would be 14), but that is impossible.
Therefore, team B must have played 3 games for a total of 5 points (since 16 games played means 16 points). So,
team B won 2, lost 0, and tied 1 (to get 5 points).
Since the total of teams E, C, and B is 2 wins, 2 losses, and 4 ties, the records of teams A and D must have the same
number of wins as losses and an even number of ties. So, there are only two possibilities:
Team | Won | Lost | Tie |
---|---|---|---|
A | 1 | 0 | 3 |
D | 0 | 1 | 3 |
or
Team | Won | Lost | Tie |
---|---|---|---|
A | 2 | 1 | 1 |
D | 1 | 2 | 1 |
But possibility #1 is impossible because Team A would have had to beat a team by 6 goals (if they only won one game), but no other team could have lost a game by 6 goals.
Correctly solved by:
1. David & Judy Dixon | Bennettsville, South Carolina |
2. Richard K. Johnson | La Jolla, California |