A man divided his estate among his three children in the following manner:
The oldest child received $3,600.
The second child received 20% more than the oldest child and 25% more than the youngest.
How much money was bequeathed to the youngest?
Solution to the Problem:
The third child would get $3,456.
The second child gets 20% more than the oldest child (who got $3,600).
So, the second child got $3,600 plus 20% of $3,600, for a total of $4,320.
Since the second child gets 25% more than the youngest child,
4320 = 1.25 x, where x is the amount that the youngest gets.
Solving the equation, x = 3456.
Correctly solved by:
| 1. John C. Funk | Ventura, California |
| 2. David & Judy Dixon | Bennettsville, South Carolina |
| 3. Les Walker | Ventura, California |