March 2009
Problem of the Month

Harry Potter Cryptarithm
by Truman Collins

Each letter of the alphabet stands for a different digit from 0 to 9 throughout this addition problem.
Can you break the code?

	G	E	O	R	G	E
		G	I	N	N	Y
	+			R	O	N
--	--	--	--	--	--	--
	P	O	T	T	E	R

You may send in your answer in the following form:
E =
G =
I =
N =
O =
P =
R =
T =
Y =

Solution to the Problem:

  
E=8 G=4 I=0 N=1 O=2 
P=5 R=6 T=3 Y=7 

 482648    
  40117
+   621
-------
 523386

Correctly solved by:

1. K. Sengupta	Calcutta, INDIA
2. Richard K. Johnson	La Jolla, California

Send any comments or questions to: David Pleacher