Three dollar bills were exchanged for a certain number of nickels and the same number of dimes.
How many nickels were there?
You must show your algebra.
Solution to the Problem:
There were 20 nickels.Let x = number of dimes = number of nickels.
5x + 10x = 300
x = 20.
Correctly solved by:
1. Ivy Joseph | Pune, Maharashtra, India |
2. Garima Mandwani | Pune, Maharashtra, India |
3. Rob Miles | Northbrook, Illinois |
4. James Alarie | Flint, Michigan |
5. Don Norris | Watkinsville, Georgia |
6. Mishan Kasiparsad | Johannesburg, South Africa |