Solution to the Problem:
You should bet on 6 or 12, each of which can be produced four different ways (6 will win on a throw of 1-6, 2-3, 3-2, or 6-1; 12 will win on 2-6, 3-4, 4-3, or 6-2).
If you place such a bet, your chance of winning is 4/36 or 1/9. Since you win $10 for a successful bet of $1, your expected return on a $1 bet is 1/9 of
$10 or about $1.11. Therefore, you should win in the long run (and the casino should discontinue the game).