2A + B + C = 27 C + B + D + A = 32 D + E + 2C = 54 2D + E + A = 57 2E + B + C = 73Then rearrange the equations with the similar letters underneath:
2A + B + C = 27 A + B + C + D = 32 2C + D + E = 54 A + 2D + E = 57 B + C + 2E = 73Since there are as many equations as variables (and none of the equations are equivalent), then there must be a solution.
2A + B + C = 27 A + B + C + D = 32 -A + 2C - D = -3 -2A + B + C - 4D = -41Now you can eliminate one of the other variables like D in the same manner.
1. Colin (Yowie) Bowey | Beechworth, Victoria, Australia |
2. Veena Mg | Bangalore, Karnataka, India |
3. Tyler Mack |
Redlands Middle School, Grand Junction, Colorado |
4. Mitchell Yerkes |
Redlands Middle School, Grand Junction, Colorado |
5. Ivy Joseph | Pune, Maharashtra, India |
6. Katherine Grossman |
Redlands Middle School, Grand Junction, Colorado |
7. Cassidy Hunter |
Delta High School, Delta, Colorado |
8. Taylor Balding |
Redlands Middle School, Grand Junction, Colorado |
9. John Simmons | Memphis, Tennessee |