Solution:
Mr. de Marco is 45 years old.
Mrs. de Marco is 39 years old.
Jackie is 9 years old.
Tony is 15 years old.
EXPLANATION:
Let the respective ages (in years) of Mrs. de Marco, Mrs. de Marco, Jackie and Tony be M, F , G and B respectively.
We denote the sum of squares of the digits of a given number by s.s.d.
Then, by conditions of the problem:
(1) M - G = 5 (B - G);
(2) M +9 = F - B;
(3) M + 6 = 3 (G+6)
(4) s.s.d. (F) = M +2
M - 3G = 12 ( from (3) ) and M + 4G = 5B (from (1))
This gives, 5B - 7G = 12-----------(5)
Since (B,G) = (8,4) is an integer solution for (5), we can take B = 7k + 8, where k must be a non negative integer, giving G = 5k + 4; so that M = 3G +12 = 15k + 24.
Accordingly, from (2); F = M+B- 9; giving, F = 22k + 23, so that:
(M, F) = (15k +24, 22k +23); where k is a non negative integer.
Consequently, (M, F) = (24,19); (39, 41); (54, 63); (69, 85) and (84, 107) are the only available choices keeping in mind the normal life span of a human being. Of the above choices,
only (M, F) = (39, 41) satisfies condition (4), since:
4^2 + 5^2 = 41 = 39 +2.;
so that k = (39-24)/15 =1
It can easily be verified that Condition (4) is not satisfied for any other choices of (M, F).
Therefore, G = 5*1 + 4 = 9 and B = 7*1 + 8 = 15. Consequently, the respective ages of Mr. de Marco, Mrs. de Marco, Jackie and Tony are 45 years, 39 years, 9 years and 15 years.
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