Ten circles of radius m are stacked together as shown in the diagram below.
Determine the distance from the top of the "pyramid" to the bottom.
Solution to the Problem:
The height of the pyramid is 3 √ 3 m + 2 m ~ 3.732 m
△ ABC is equilateral (each side is 6 m long).
AD = 3 m.
m ∠ A = 60°.
m ∠ ADC = 90°.
CD = 3 √ 3 m.
So the height of the pyramid is 3 √ 3 m + 2 m.
Correctly solved by:
| 1. Davit Banana | Istanbul, Turkey |
| 2. Colin (Yowie) Bowey | Beechworth, Victoria, Australia |
| 3. Dr. Hari Kishan |
D.N. College, Meerut, Uttar Pradesh, India |
| 4. Ritwik Chaudhuri | Santiniketan, West Bengal, India |